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What is the amplitude of 
h(x)=-5cos(2pi x+5)-2?
units

What is the amplitude of h(x)=5cos(2πx+5)2? h(x)=-5 \cos (2 \pi x+5)-2 ? \newlineunits

Full solution

Q. What is the amplitude of h(x)=5cos(2πx+5)2? h(x)=-5 \cos (2 \pi x+5)-2 ? \newlineunits
  1. Identify standard form: Identify the standard form of a cosine function and the amplitude.\newlineThe standard form of a cosine function is Acos(Bx+C)+DA\cos(Bx + C) + D, where AA is the amplitude, BB affects the period, CC is the phase shift, and DD is the vertical shift.
  2. Compare with given function: Compare the given function h(x)=5cos(2πx+5)2h(x)=-5\cos(2\pi x+5)-2 with the standard form.\newlineIn the given function, A=5A = -5, B=2πB = 2\pi, C=5C = 5, and D=2D = -2. The amplitude is the absolute value of AA.
  3. Calculate amplitude: Calculate the amplitude.\newlineThe amplitude is Aext,whichis5|A| ext{, which is }|-5|. Therefore, the amplitude is 55.