The speed of sound in air is about 332 meters per second ((m)/(s)) at 0 degrees Celsius (^(@)C). If the speed increases by 0.6(m)/(s) for every increase in temperature of 1^(@)C, which inequality best represents the temperatures, T, in degrees Celsius, for which the speed of sound in air exceeds 350(m)/(s) ? Choose 1 answer: (A) T 30 (D) T >= 30

Given Information: We are given that the speed of sound in air at 0 degrees Celsius is 332 meters per second. We are also told that the speed increases by 0.6 meters per second for every 1 degree Celsius increase in temperature. We need to find the temperature at which the speed of sound exceeds 350 meters per second. Let's denote the temperature in degrees Celsius as T.Equation Setup: First, we need to set up an equation that relates the speed of sound to the temperature. The speed of sound at any temperature T can be represented as 332 + 0.6T, where 332 is the speed of sound at 0 degrees Celsius and 0.6T is the increase in speed for T degrees above 0 degrees Celsius.Inequality Setup: Next, we want to find the value of T for which the speed of sound exceeds 350 meters per second. This means we need to solve the inequality 332 + 0.6T > 350.Subtract 332: To solve for T, we subtract 332 from both sides of the inequality: 0.6T > 350 - 332.Divide by 0.6: Performing the subtraction gives us 0.6T > 18.Final Result: Now, we divide both sides of the inequality by 0.6 to solve for T: T > 18 / 0.6.Dividing 18 by 0.6 gives us T > 30.Therefore, the inequality that represents the temperatures for which the speed of sound in air exceeds 350 meters per second is T > 30.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The speed of sound in air is about 332 meters per second
((m)/(s)) at 0 degrees Celsius
(^(@)C). If the speed increases by
0.6(m)/(s) for every increase in temperature of
1^(@)C, which inequality best represents the temperatures,
T, in degrees Celsius, for which the speed of sound in air exceeds
350(m)/(s) ?
Choose 1 answer:
(A)
T < 30
(B)
T <= 30
(c)
T > 30
(D)
T >= 30

The speed of sound in air is about $332$ meters per second $\left(\frac{\mathrm{m}}{\mathrm{s}}\right)$ at $0$ degrees Celsius $\left({ }^{\circ} \mathrm{C}\right)$ . If the speed increases by $0.6 \frac{\mathrm{m}}{\mathrm{s}}$ for every increase in temperature of $1^{\circ} \mathrm{C}$ , which inequality best represents the temperatures, $T$ , in degrees Celsius, for which the speed of sound in air exceeds $350 \frac{\mathrm{m}}{\mathrm{s}}$ ? $\newline$ Choose $1$ answer: $\newline$ (A) T<30 $\newline$ (B) $T \leq 30$ $\newline$ (C) T>30 $\newline$ (D) $T \geq 30$

View step-by-step help

Home

Math Problems

Algebra 2

Write a linear inequality: word problems

Full solution

Q. The speed of sound in air is about

332

meters per second

\left(\frac{\mathrm{m}}{\mathrm{s}}\right)

0

degrees Celsius

\left({ }^{\circ} \mathrm{C}\right)

. If the speed increases by

0.6 \frac{\mathrm{m}}{\mathrm{s}}

for every increase in temperature of

1^{\circ} \mathrm{C}

, which inequality best represents the temperatures,

T

, in degrees Celsius, for which the speed of sound in air exceeds

350 \frac{\mathrm{m}}{\mathrm{s}}

\newline

Choose

1

answer:

\newline

(A)

T<30

\newline

(B)

T \leq 30

\newline

(C)

T>30

\newline

(D)

T \geq 30

Given Information: We are given that the speed of sound in air at $0$ degrees Celsius is $332$ meters per second. We are also told that the speed increases by $0.6$ meters per second for every $1$ degree Celsius increase in temperature. We need to find the temperature at which the speed of sound exceeds $350$ meters per second. Let's denote the temperature in degrees Celsius as $T$ .
Expression Setup: First, we need to set up an equation that relates the speed of sound to the temperature. The speed of sound at any temperature $T$ can be represented as $332 + 0.6T$ , where $332$ is the speed of sound at $0$ degrees Celsius and $0.6T$ is the increase in speed for $T$ degrees above $0$ degrees Celsius.
Inequality Setup: Next, we want to find the value of $T$ for which the speed of sound exceeds $350$ meters per second. This means we need to solve the inequality 332 + 0.6T > 350.
Subtract $332$ : To solve for $T$ , we subtract $332$ from both sides of the inequality: $\newline$ 0.6T > 350 - 332
Perform Subtraction: Performing the subtraction gives us 0.6T > 18.
Divide by $0$ . $6$ : Now, we divide both sides of the inequality by $0.6$ to solve for $T$ : $\newline$ T > \frac{18}{0.6}
Final Result: Dividing $18$ by $0.6$ gives us T > 30. $\newline$ Therefore, the inequality that represents the temperatures for which the speed of sound in air exceeds $350$ meters per second is T > 30.