The power generated by an electrical circuit (in watts) as a function of its current x (in amperes) is modeled byP(x)=−15x(x−8)What current will produce the maximum power?amperes
Q. The power generated by an electrical circuit (in watts) as a function of its current x (in amperes) is modeled byP(x)=−15x(x−8)What current will produce the maximum power?amperes
Rewrite Quadratic Function: To find the current that will produce the maximum power, we need to find the vertex of the parabola represented by the quadratic function P(x)=−15x(x−8). First, we need to rewrite the function in standard form.P(x)=−15x2+120xThe quadratic function is in the form P(x)=ax2+bx+c. Here, a=−15 and b=120.
Find Parabola Vertex:P(x)=−15x2+120xSince the coefficient of x2 is negative (−15), the parabola opens downwards, and the vertex will give us the maximum point.
Calculate x-coordinate: To find the x-coordinate of the vertex, we use the formula −2ab. Now we apply the formula to find the x-coordinate of the vertex: x=−2ab=−2×−15120=−−30120=4
Verify Calculations: The x-coordinate of the vertex is 4 amperes. This is the current that will produce the maximum power in the electrical circuit.To ensure there are no math errors, we can check our calculations:−15×4×(4−8)=−15×4×−4=240This is a positive value, and since the parabola opens downwards, it confirms that the vertex is indeed a maximum point.
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