The graph of a line in the xy-plane has a slope of 1 and contains the point (3,0). The graph of a second line has a slope of −41 and contains the point (−7,0). If the two lines intersect at the point (a,b), what is the value of a+b ?Choose 1 answer:(A) −8(B) −5(C) −2(D) −1
Q. The graph of a line in the xy-plane has a slope of 1 and contains the point (3,0). The graph of a second line has a slope of −41 and contains the point (−7,0). If the two lines intersect at the point (a,b), what is the value of a+b ?Choose 1 answer:(A) −8(B) −5(C) −2(D) −1
Find equation of first line: First, let's find the equation of the first line with a slope of 1 that passes through the point (3,0).The slope-intercept form of a line is y=mx+b, where m is the slope and b is the y-intercept.Since the slope (m) is 1 and the line passes through (3,0), we can substitute these values into the equation to find b.y=mx+b0=(1)(3)+b0=3+bb=−3Now, substitute the value of m and b in y=mx+b.So, the equation of the first line is y=x−3.
Find equation of second line: Next, let's find the equation of the second line with a slope of −41 that passes through the point (−7,0). Again, using the slope-intercept form y=mx+b, we substitute the slope and the point into the equation to find b. y=mx+b0=−41(−7)+b0=47+bb=−47Now, substitute the value of m and b in y=mx+b. So, the equation of the second line is y=−41x−47.
Find intersection point: Now, to find the intersection point(a,b) of the two lines, we set their equations equal to each other since at the point of intersection, their y-values will be the same.x−3=−(41)x−47To solve for x, we combine like terms.x+(41)x=−47+3(45)x=45x=45×54x=1
Find coordinates of intersection point: Having found the x-coordinate of the intersection point, we now substitute x=1 into either of the line equations to find the y-coordinate. We'll use the first line's equation for simplicity.y=x−3y=1−3y=−2So, the intersection point (a,b) is (1,−2).
Find value of a+b: Finally, we find the value of a+b.a+b=1+(−2)a+b=−1
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