The formula for the size of a file that was downloaded over time t and at an average rate r is r⋅t. Siena downloaded a file at a rate of 800 kilobytes per second for about 110 seconds. What calculation will give us the estimated size of the file Siena downloaded, in megabytes? Choose 1 answer:(A) 800⋅110⋅60(B) 800⋅60110(C) 800⋅1000⋅110(D) 1000800⋅110
Q. The formula for the size of a file that was downloaded over time t and at an average rate r is r⋅t. Siena downloaded a file at a rate of 800 kilobytes per second for about 110 seconds. What calculation will give us the estimated size of the file Siena downloaded, in megabytes? Choose 1 answer:(A) 800⋅110⋅60(B) 800⋅60110(C) 800⋅1000⋅110(D) 1000800⋅110
Identify Formula: Identify the formula to use for the calculation.The formula given is r∗t, where r is the rate of download and t is the time taken to download the file.
Plug in Values: Plug in the values for r and t into the formula.Siena downloaded a file at a rate of 800 kilobytes per second for about 110 seconds.So, r=800 kilobytes/second and t=110 seconds.
Calculate Size: Calculate the size of the file in kilobytes.Using the formula r∗t, we get 800 kilobytes/second ∗110 seconds =88000 kilobytes.
Convert to Megabytes: Convert the file size from kilobytes to megabytes.There are 1000 kilobytes in a megabyte. Therefore, to convert kilobytes to megabytes, we divide by 1000.88000 kilobytes ÷1000=88 megabytes.
Match with Choices: Match the calculation with the given choices.The correct calculation is (800 kilobytes/second)×110 seconds/1000=88 megabytes.This matches with choice (B) 800×(110)/(60), if we recognize that the division by 60 is incorrect and should be division by 1000 to convert kilobytes to megabytes. Therefore, none of the given choices are correct.
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