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The equation 
-x-2y=0 is graphed in the 
xy-plane. Which of the following is a true statement about the graph?
Choose 1 answer:
A The graph goes through the point 
(-1,2).
(B) The graph has a slope of 2.
(C) The graph goes through the point 
(0,0).
(D) The graph has a slope of 
(1)/(2).

The equation x2y=0 -x-2 y=0 is graphed in the xy x y -plane. Which of the following is a true statement about the graph?\newlineChoose 11 answer:\newlineA The graph goes through the point (1,2) (-1,2) .\newlineB The graph has a slope of 22.\newline(C) The graph goes through the point (0,0) (0,0) .\newlineD The graph has a slope of 12 \frac{1}{2} .

Full solution

Q. The equation x2y=0 -x-2 y=0 is graphed in the xy x y -plane. Which of the following is a true statement about the graph?\newlineChoose 11 answer:\newlineA The graph goes through the point (1,2) (-1,2) .\newlineB The graph has a slope of 22.\newline(C) The graph goes through the point (0,0) (0,0) .\newlineD The graph has a slope of 12 \frac{1}{2} .
  1. Rewrite Equation: First, we need to rewrite the equation in slope-intercept form, which is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.\newlineThe given equation is x2y=0-x - 2y = 0. To rewrite it, we solve for yy:\newline2y=x-2y = x\newliney=(12)xy = (-\frac{1}{2})x
  2. Identify Slope and Y-Intercept: Now that we have the equation in slope-intercept form, we can identify the slope and y-intercept. The slope mm is 12-\frac{1}{2}, and the y-intercept bb is 00 since there is no constant added to the mxmx term.
  3. Evaluate Answer Choices (A): We can now evaluate the answer choices based on the slope-intercept form of the equation:\newline(A) The graph goes through the point (1,2)(-1,2). To check this, we can substitute x=1x = -1 and y=2y = 2 into the equation y=(12)xy = (-\frac{1}{2})x and see if it holds true:\newline2=(12)(1)2 = (-\frac{1}{2})(-1)\newline2=122 = \frac{1}{2}\newlineThis is not true, so option (A) is incorrect.
  4. Evaluate Answer Choices (B): (B) The graph has a slope of 22. We have already determined that the slope is , so option (B) is incorrect.
  5. Evaluate Answer Choices (C): (C) The graph goes through the point (0,0)(0,0). To check this, we can substitute x=0x = 0 and y=0y = 0 into the equation y=(12)xy = (-\frac{1}{2})x: \newline0=(12)(0)0 = (-\frac{1}{2})(0)\newline0=00 = 0\newlineThis is true, so option (C) is a possible correct answer.
  6. Evaluate Answer Choices (D): (D) The graph has a slope of 12\frac{1}{2}. We have already determined that the slope is 12-\frac{1}{2}, not 12\frac{1}{2}, so option (D) is incorrect.

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