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The equation 
6y+12 x=18 is graphed in the 
xy-plane. Which of the following equations has a graph that is perpendicular to the graph of the given equation?
Choose 1 answer:
(A) 
y=-2x+3
(B) 
y=(1)/(2)x+3
(C) 
y=2x+3
(D) 
y=-(1)/(2)x+3

The equation 6y+12x=18 6 y+12 x=18 is graphed in the xy x y -plane. Which of the following equations has a graph that is perpendicular to the graph of the given equation?\newlineChoose 11 answer:\newline(A) y=2x+3 y=-2 x+3 \newline(B) y=12x+3 y=\frac{1}{2} x+3 \newline(C) y=2x+3 y=2 x+3 \newline(D) y=12x+3 y=-\frac{1}{2} x+3

Full solution

Q. The equation 6y+12x=18 6 y+12 x=18 is graphed in the xy x y -plane. Which of the following equations has a graph that is perpendicular to the graph of the given equation?\newlineChoose 11 answer:\newline(A) y=2x+3 y=-2 x+3 \newline(B) y=12x+3 y=\frac{1}{2} x+3 \newline(C) y=2x+3 y=2 x+3 \newline(D) y=12x+3 y=-\frac{1}{2} x+3
  1. Find slope of line: Find the slope of the given line.\newlineThe equation of the given line is 6y+12x=186y + 12x = 18. To find the slope, we need to rewrite it in slope-intercept form, which is y=mx+by = mx + b, where mm is the slope.
  2. Rewrite equation in slope-intercept form: Rewrite the given equation in slope-intercept form.\newlineStarting with 6y+12x=186y + 12x = 18, we subtract 12x12x from both sides to get 6y=12x+186y = -12x + 18. Then, we divide each term by 66 to solve for yy, which gives us y=2x+3y = -2x + 3. The slope of this line is 2-2.
  3. Determine slope of perpendicular line: Determine the slope of the line that is perpendicular to the given line.\newlineThe slope of the line perpendicular to the given line is the negative reciprocal of the slope of the given line. Since the slope of the given line is 2-2, the negative reciprocal is 12\frac{1}{2}.
  4. Identify equation with negative reciprocal slope: Identify the equation with the slope that is the negative reciprocal of the given line's slope.\newlineWe are looking for an equation with a slope of 12\frac{1}{2}. Among the options given:\newline(A) y=2x+3y = -2x + 3 has a slope of 2-2.\newline(B) y=(12)x+3y = \left(\frac{1}{2}\right)x + 3 has a slope of 12\frac{1}{2}.\newline(C) y=2x+3y = 2x + 3 has a slope of 22.\newline(D) y=(12)x+3y = -\left(\frac{1}{2}\right)x + 3 has a slope of 12-\frac{1}{2}.\newlineThe correct equation is the one with the slope of 12\frac{1}{2}, which is option (B).

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