The equation 5x+4y=1 is graphed in the xy-plane. Which of the following is a true statement about the graph? Choose 1 answer: (A) The graph's y-intercept is (1)/(5). B The graph's x-intercept is -(1)/(4). (c) The graph has a slope of -(5)/(4). (D) The graph has a slope of -(4)/(5).

Find y-intercept: To find the y-intercept, we set x to 0 and solve for y. 5(0) + 4y = 1 4y = 1 y = 1/4 The y-intercept is (0, 1/4), not (1/5).Find x-intercept: To find the x-intercept, we set y to 0 and solve for x. 5x + 4(0) = 1 5x = 1 x = 1/5 The x-intercept is (1/5, 0), not -(1/4).Find slope: To find the slope of the graph, we can rewrite the equation in slope-intercept form (y = mx + b), where m is the slope. 4y = -5x + 1 y = (-5/4)x + 1/4 The slope of the graph is -5/4, which matches option (C).

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Algebra 1

Slopes of parallel and perpendicular lines

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Q. The equation

5 x+4 y=1

is graphed in the

x y

-plane. Which of the following is a true statement about the graph?

\newline

Choose

1

answer:

\newline

(A) The graph's

y

-intercept is

\frac{1}{5}

\newline

(B) The graph's

x

-intercept is

-\frac{1}{4}

\newline

-\frac{5}{4}

\newline

(D) The graph has a slope of

-\frac{4}{5}

Find y-intercept: To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $5(0) + 4y = 1$ $4y = 1$ $y = \frac{1}{4}$ The y-intercept is $(0, \frac{1}{4})$ , not $(\frac{1}{5})$ .
Find x-intercept: To find the x-intercept, we set $y$ to $0$ and solve for $x$ . $\newline$ $5x + 4(0) = 1$ $\newline$ $5x = 1$ $\newline$ $x = \frac{1}{5}$ $\newline$ The x-intercept is $(\frac{1}{5}, 0)$ , not $-(\frac{1}{4})$ .
Find slope: To find the slope of the graph, we can rewrite the equation in slope-intercept form $y = mx + b$ , where $m$ is the slope. $4y = -5x + 1$ $y = (-5/4)x + 1/4$ The slope of the graph is $-5/4$ , which matches option (C).