The equation 3x−2y=4 is graphed in the xy-plane. Which of the statements is true of its graph?Choose 1 answer:(A) The graph is a line parallel to the line whose equation is y=−32x+1.(B) The graph is a line perpendicular to the line whose equation isy=−32x+1. (C) The graph is a line with a slope of −32.(D) The graph is a line with a slope of −23.
Q. The equation 3x−2y=4 is graphed in the xy-plane. Which of the statements is true of its graph?Choose 1 answer:(A) The graph is a line parallel to the line whose equation is y=−32x+1.(B) The graph is a line perpendicular to the line whose equation isy=−32x+1. (C) The graph is a line with a slope of −32.(D) The graph is a line with a slope of −23.
Rewrite Equation: First, let's rewrite the given equation 3x−2y=4 in slope-intercept form, which is y=mx+b, where m is the slope and b is the y-intercept.To do this, we solve for y:3x−2y=4−2y=−3x+4y=23x−2
Identify Slope: Now that we have the equation in slope-intercept form, we can identify the slope of the line. The slope is the coefficient of x, which in this case is 23.
Compare Slopes: Let's compare the slope of our line with the slopes given in the answer choices:A) The line y=−32x+1 has a slope of −32. Our line has a slope of 23, which is not the same, so this statement is false.B) To be perpendicular, the slopes of two lines must be negative reciprocals of each other. The negative reciprocal of 23 is −32, which matches the slope of the line in choice B. Therefore, this statement is true.C) The graph of our line does not have a slope of −32, so this statement is false.D) The graph of our line does not have a slope of −23, so this statement is false.
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