Solve the equation. {:[(3)/(2)+b=(7)/(4)],[b=]:}

Write Equation: Write down the equation that needs to be solved. (3/2) + b = (7/4)Isolate b: To find the value of b, we need to isolate b on one side of the equation. We can do this by subtracting (3/2) from both sides of the equation. b = (7/4) - (3/2)Convert Fractions: Convert the fractions to have a common denominator before subtracting. The common denominator for 4 and 2 is 4. b = (7/4) - (3/2) * (2/2) b = (7/4) - (6/4)Subtract Fractions: Now subtract the fractions. b = (7/4) - (6/4) b = (7 - 6)/4 b = 1/4

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Solve the equation.

{:[(3)/(2)+b=(7)/(4)],[b=]:}

Solve the equation. $\newline$ $\begin{array}{l} \frac{3}{2}+b=\frac{7}{4} \\ b= \end{array}$

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Math Problems

Grade 6

Multiply two decimals: where does the decimal point go?

Full solution

Q. Solve the equation.

\newline

\begin{array}{l} \frac{3}{2}+b=\frac{7}{4} \\ b= \end{array}

Write Equation: Write down the equation that needs to be solved. $\newline$ $(\frac{3}{2}) + b = (\frac{7}{4})$
Isolate $b$ : To find the value of $b$ , we need to isolate $b$ on one side of the equation. We can do this by subtracting $\frac{3}{2}$ from both sides of the equation. $\newline$ $b = \frac{7}{4} - \frac{3}{2}$
Convert Fractions: Convert the fractions to have a common denominator before subtracting. The common denominator for $4$ and $2$ is $4$ . $\newline$ b = \left(\frac{ $7$ }{ $4$ }\right) - \left(\frac{ $3$ }{ $2$ }\right) \times \left(\frac{ $2$ }{ $2$ }\right) $\newline$ b = \left(\frac{ $7$ }{ $4$ }\right) - \left(\frac{ $6$ }{ $4$ }\right)
Subtract Fractions: Now subtract the fractions. $\newline$ b = $(\frac{7}{4}) - (\frac{6}{4})$ $\newline$ b = $(\frac{7 - 6}{4})$ $\newline$ b = $\frac{1}{4}$