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Solve for x. {:[x^(2)-2x+1=0],[x=◻]:}

Solve for x x .\newlinex2−2x+1=0 x^{2}-2 x+1=0 \newlinex= x=

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Full solution

Q. Solve for x x .\newlinex2−2x+1=0 x^{2}-2 x+1=0 \newlinex= x=
  1. Identify Quadratic Equation: Identify the first equation as a quadratic equation and recognize that it is in the form of a perfect square trinomial.\newlinex2−2x+1=0x^2 - 2x + 1 = 0
  2. Factor Perfect Square Trinomial: Factor the perfect square trinomial. (x−1)(x−1)=0(x - 1)(x - 1) = 0
  3. Solve for x: Set each factor equal to zero and solve for x.\newlinex−1=0x - 1 = 0\newlinex=1x = 1
  4. Unique Solution: Since both factors are the same, there is only one unique solution to the quadratic equation. x=1x = 1
  5. Incomplete Second Equation: The second equation in the system is x=□x = \square, which is not a complete equation. It seems there is a placeholder where a number or expression should be. Without additional information, we cannot proceed with solving the system.

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