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Solve for 
x. Enter the solutions from least to greatest.

{:[(x+6)^(2)-16=0],[" lesser "x=◻],[" greater "x=◻]:}

Solve for x x . Enter the solutions from least to greatest.\newline(x+6)216=0 lesser x= greater x= \begin{array}{l} (x+6)^{2}-16=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}

Full solution

Q. Solve for x x . Enter the solutions from least to greatest.\newline(x+6)216=0 lesser x= greater x= \begin{array}{l} (x+6)^{2}-16=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
  1. Write and Identify Equation: Write down the given equation and identify the type of equation.\newlineThe given equation is (x+6)216=0(x+6)^2 - 16 = 0. This is a quadratic equation in the form of a perfect square trinomial minus a constant.
  2. Factor using Difference of Squares: Factor the equation using the difference of squares formula.\newlineThe equation (x+6)216=0(x+6)^2 - 16 = 0 can be factored as ((x+6)+4)((x+6)4)=0((x+6) + 4)((x+6) - 4) = 0, because 1616 is a perfect square and can be written as 424^2.
  3. Set Factors Equal and Solve: Set each factor equal to zero and solve for xx.
    (x+6)+4=0(x+6) + 4 = 0 or (x+6)4=0(x+6) - 4 = 0
    This gives us two separate equations to solve:
    11. x+6+4=0x + 6 + 4 = 0
    22. x+64=0x + 6 - 4 = 0
  4. Solve First Equation: Solve the first equation for xx.x+10=0x + 10 = 0Subtract 1010 from both sides:x=10x = -10
  5. Solve Second Equation: Solve the second equation for xx.x+2=0x + 2 = 0Subtract 22 from both sides:x=2x = -2
  6. Identify Lesser and Greater Solutions: Identify the lesser and greater solutions.\newlineThe lesser value of xx is 10-10, and the greater value of xx is 2-2.

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