Solve for x. Enter the solutions from least to greatest. {:[(x-4)(-5x+1)=0],[" lesser "x=◻],[" greater "x=◻]:}

Factored Equation: Factored equation: (x-4)(-5x+1)=0 To find the roots, set each factor equal to zero and solve for x.First Factor: First factor: x - 4 = 0 Solve for x: x - 4 + 4 = 0 + 4 x = 4Second Factor: Second factor: -5x + 1 = 0 Solve for x: -5x + 1 - 1 = 0 - 1 -5x = -1 x = -1 / -5 x = 1/5 or 0.2Final Solutions: Now we have two solutions for x: 4 and 0.2. We need to enter the solutions from least to greatest. 0.2 is less than 4.

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Solve for
x.
Enter the solutions from least to greatest.

{:[(x-4)(-5x+1)=0],[" lesser "x=◻],[" greater "x=◻]:}

Solve for $x$ . $\newline$ Enter the solutions from least to greatest. $\newline$ $\begin{array}{l} (x-4)(-5 x+1)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}$

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Math Problems

Algebra 2

Find the roots of factored polynomials

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Q. Solve for

x

\newline

Enter the solutions from least to greatest.

\newline

\begin{array}{l} (x-4)(-5 x+1)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}

Factored Equation: Factored equation: $(x-4)(-5x+1)=0$ $\newline$ To find the roots, set each factor equal to zero and solve for $x$ .
First Factor: First factor: $x - 4 = 0$ $\newline$ Solve for x: $\newline$ $x - 4 + 4 = 0 + 4$ $\newline$ $x = 4$
Second Factor: Second factor: $-5x + 1 = 0$ Solve for $x$ : $-5x + 1 - 1 = 0 - 1$ $-5x = -1$ $x = -1 / -5$ $x = 1/5$ or $0.2$
Final Solutions: Now we have two solutions for $x$ : $4$ and $0.2$ . We need to enter the solutions from least to greatest. $0.2$ is less than $4$ .