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Solve for x. Enter the solutions from least to greatest. {:[x^(2)+3x-4=0],[" lesser "x=◻],[" greater "x=◻]:}

Solve for x x . Enter the solutions from least to greatest.\newlinex2+3x−4=0 lesser x=□ greater x=□ \begin{array}{l} x^{2}+3 x-4=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}

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Q. Solve for x x . Enter the solutions from least to greatest.\newlinex2+3x−4=0 lesser x=□ greater x=□ \begin{array}{l} x^{2}+3 x-4=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
  1. Identify the quadratic equation: Identify the quadratic equation to be solved.\newlineWe have the quadratic equation x2+3x−4=0x^2 + 3x - 4 = 0. We need to find two numbers that multiply to −4-4 (the constant term) and add up to 33 (the coefficient of the xx term).
  2. Factor the quadratic equation: Factor the quadratic equation.\newlineThe two numbers that multiply to −4-4 and add up to 33 are 44 and −1-1.\newlineSo, we can write the equation as (x+4)(x−1)=0(x + 4)(x - 1) = 0.
  3. Solve for x using the zero product property: Solve for x using the zero product property.\newlineIf (x+4)(x−1)=0(x + 4)(x - 1) = 0, then either x+4=0x + 4 = 0 or x−1=0x - 1 = 0.\newlineFor x+4=0x + 4 = 0:\newlinex=−4x = -4\newlineFor x−1=0x - 1 = 0:\newlinex=1x = 1
  4. Write the solutions in ascending order: Write the solutions in ascending order.\newlineThe lesser value of xx is −4-4, and the greater value of xx is 11.

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