Solve for x. Enter the solutions from least to greatest. {:[(x+1)(3x+4)=0],[" lesser "x=◻],[" greater "x=◻]:}

Factor the polynomial: Factored polynomial: (x + 1)(3x + 4) Which equation finds the roots for this polynomial? Set the polynomial equal to zero. (x + 1)(3x + 4) = 0Find roots equation: x + 1 = 0 What is the value of x? x + 1 = 0 x + 1 - 1 = 0 - 1 x = -1Set polynomial equal to zero: 3x + 4 = 0 What is the value of x? 3x + 4 = 0 3x + 4 - 4 = 0 - 4 3x = -4 x = -4/3Find x value: We know: x = -1 x = -4/3 Write the roots of the polynomial in ascending order. x = -4/3 x = -1 Roots of the polynomial: -4/3, -1

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Math Problems

Algebra 2

Find the roots of factored polynomials

Full solution

Q. Solve for

x

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Enter the solutions from least to greatest.

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(x+1)(3 x+4)=0

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lesser

x=

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greater

x=

Factor the polynomial: Factored polynomial: $(x + 1)(3x + 4)$ $\newline$ Which equation finds the roots for this polynomial? $\newline$ Set the polynomial equal to zero. $\newline$ $(x + 1)(3x + 4) = 0$
Find roots equation: $x + 1 = 0$ $\newline$ What is the value of $x$ ? $\newline$ $x + 1 = 0$ $\newline$ $x + 1 - 1 = 0 - 1$ $\newline$ $x = -1$
Set polynomial equal to zero: $3x + 4 = 0$ $\newline$ What is the value of $x$ ? $\newline$ $3x + 4 = 0$ $\newline$ $3x + 4 - 4 = 0 - 4$ $\newline$ $3x = -4$ $\newline$ $x = -\frac{4}{3}$
Find $x$ value: We know: $\newline$ $x = -1$ $\newline$ $x = -\frac{4}{3}$ $\newline$ Write the roots of the polynomial in ascending order. $\newline$ $x = -\frac{4}{3}$ $\newline$ $x = -1$ $\newline$ Roots of the polynomial: $-\frac{4}{3}$ , $-1$