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Solve for 
x. Enter the solutions from least to greatest.

{:[(x+1)^(2)-36=0],[" lesser "x=◻],[" greater "x=◻]:}

Solve for x x . Enter the solutions from least to greatest.\newline(x+1)236=0 lesser x= greater x= \begin{array}{l} (x+1)^{2}-36=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}

Full solution

Q. Solve for x x . Enter the solutions from least to greatest.\newline(x+1)236=0 lesser x= greater x= \begin{array}{l} (x+1)^{2}-36=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
  1. Identify the equation: Identify the equation to solve.\newlineWe are given the equation (x+1)236=0(x+1)^2 - 36 = 0. We need to solve for xx.
  2. Add 3636 to isolate the squared term: Add 3636 to both sides of the equation to isolate the squared term.\newline(x+1)236+36=0+36(x+1)^2 - 36 + 36 = 0 + 36\newline(x+1)2=36(x+1)^2 = 36
  3. Take square root to solve for x+1x+1: Take the square root of both sides of the equation to solve for x+1x+1.(x+1)2=36\sqrt{(x+1)^2} = \sqrt{36}x+1=±6x+1 = \pm 6
  4. Solve for x: Solve for x by subtracting 11 from both sides of the equation for both positive and negative cases.\newlineFor the positive case:\newlinex+1=6x + 1 = 6\newlinex=61x = 6 - 1\newlinex=5x = 5\newlineFor the negative case:\newlinex+1=6x + 1 = -6\newlinex=61x = -6 - 1\newlinex=7x = -7
  5. List solutions from least to greatest: List the solutions from least to greatest.\newlineThe lesser xx is 7-7 and the greater xx is 55.

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