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Solve for 
x. Enter the solutions from least to greatest.

{:[4x^(2)+72 x+320=0],[" lesser "x=◻],[" greater "x=◻]:}

Solve for x x . Enter the solutions from least to greatest.\newline4x2+72x+320=0 lesser x= greater x= \begin{array}{l} 4 x^{2}+72 x+320=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}

Full solution

Q. Solve for x x . Enter the solutions from least to greatest.\newline4x2+72x+320=0 lesser x= greater x= \begin{array}{l} 4 x^{2}+72 x+320=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
  1. Identify the quadratic equation: Identify the quadratic equation to be solved.\newlineWe have the quadratic equation 4x2+72x+320=04x^2 + 72x + 320 = 0.
  2. Factor out the greatest common factor: Factor out the greatest common factor if possible.\newlineIn this case, we can factor out 44 from each term.\newline4(x2+18x+80)=04(x^2 + 18x + 80) = 0
  3. Set the factored equation equal to zero: Set the factored equation equal to zero and solve for xx.\newlineNow we need to factor the quadratic expression in the parentheses.\newlineWe are looking for two numbers that multiply to 8080 and add up to 1818.\newlineThe numbers 1010 and 88 satisfy these conditions.\newlineSo we can write the factored form as:\newline4(x+10)(x+8)=04(x + 10)(x + 8) = 0
  4. Solve each factor set equal to zero: Solve each factor set equal to zero.\newlineFirst, we set x+10x + 10 equal to zero:\newlinex+10=0x + 10 = 0\newlinex=10x = -10\newlineThen, we set x+8x + 8 equal to zero:\newlinex+8=0x + 8 = 0\newlinex=8x = -8
  5. Write the solutions in ascending order: Write the solutions in ascending order.\newlineThe solutions are x=10x = -10 and x=8x = -8.\newlineSince 10-10 is less than 8-8, the solutions in ascending order are 10-10, 8-8.

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