Solve for x. Enter the solutions from least to greatest. {:[3x^(2)-9x-12=0],[" lesser "x=◻],[" greater "x=◻]:}

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Solve for  x. Enter the solutions from least to greatest.  {:[3x^(2)-9x-12=0],[" lesser "x=◻],[" greater "x=◻]:}

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Identify quadratic equation: Identify the quadratic equation to solve. 3x^2 - 9x - 12 = 0 We need to find two numbers that multiply to give the product of the coefficient of x^2 (which is 3) and the constant term (-12), and add up to the coefficient of x (-9).Find numbers that meet criteria: Find the two numbers that meet the criteria. The numbers -12 and +1 multiply to -12 and add up to -11, which is not the coefficient we need. The numbers -6 and +2 multiply to -12 and add up to -4, which is also not the coefficient we need. The numbers -4 and +3 multiply to -12 and add up to -1, which is also not the coefficient we need. The numbers -3 and +4 multiply to -12 and add up to +1, which is also not the coefficient we need. However, if we multiply these numbers by 3 (the coefficient of x^2), we get -9 and +12, which do add up to +3, but we need -9. Therefore, we need to find another pair. The numbers -3 and -4 multiply to +12 and add up to -7, which is also not the coefficient we need. The numbers -1 and -12 multiply to +12 and add up to -13, which is also not the coefficient we need. The correct pair of numbers that multiply to 3*(-12) = -36 and add up to -9 are -3 and -12.Write equation with split middle term: Write the equation with the middle term split using the two numbers found. 3x^2 - 3x - 12x - 12 = 0 Group the terms to factor by grouping. (3x^2 - 3x) + (-12x - 12) = 0 Factor out the common factors in each group. 3x(x - 1) - 12(x + 1) = 0Factor by grouping: Notice that there is a mistake in the previous step. The correct pair should be -1 and -12, which multiply to +12 and add up to -13, which is not the coefficient we need. We need to find the correct pair of numbers that multiply to 3*(-12) = -36 and add up to -9. The correct pair is -3 and -12.

Solve for $x$ . Enter the solutions from least to greatest. $\newline$ $\begin{array}{l} 3 x^{2}-9 x-12=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}$

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Solve for x x x. Enter the solutions from least to greatest.\newline3x2−9x−12=0 lesser x=□ greater x=□ \begin{array}{l} 3 x^{2}-9 x-12=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array} 3x2−9x−12=0 lesser x=□ greater x=□​

Solve for $x$ . Enter the solutions from least to greatest. $\newline$ $\begin{array}{l} 3 x^{2}-9 x-12=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}$