Solve for x. Enter the solutions from least to greatest. {:[2x^(2)-16 x+14=0],[" lesser "x=◻],[" greater "x=◻]:}

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Solve for  x. Enter the solutions from least to greatest.  {:[2x^(2)-16 x+14=0],[" lesser "x=◻],[" greater "x=◻]:}

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Identify quadratic equation: Identify the quadratic equation to solve. The given quadratic equation is 2x^2 - 16x + 14 = 0. We need to find the values of x that satisfy this equation.Factor the equation: Factor the quadratic equation if possible. To factor the equation, we need to find two numbers that multiply to give the product of the coefficient of x^2 (which is 2) and the constant term (which is 14), and add up to the coefficient of x (which is -16). The product of 2 and 14 is 28. We need two numbers that multiply to 28 and add up to -16.Find the two numbers: Find the two numbers that fit the criteria. The numbers -14 and -2 multiply to give 28 and add up to -16. So we can write -16x as -14x - 2x. The equation becomes 2x^2 - 14x - 2x + 14 = 0.Factor by grouping: Factor by grouping. We can group the terms as follows: (2x^2 - 14x) - (2x - 14) = 0. Now, factor out the common factors in each group: 2x(x - 7) - 2(x - 7) = 0. We can see that (x - 7) is a common factor.Factor out common factor: Factor out the common factor. The equation can now be written as (2x - 2)(x - 7) = 0. We can factor out a 2 from the first term to simplify it further: 2(x - 1)(x - 7) = 0.Solve for x: Solve for x. We have two factors set to zero: (x - 1) = 0 and (x - 7) = 0. Solving each equation for x gives us x = 1 and x = 7.Write the solutions: Write the solutions in ascending order. The lesser value of x is 1, and the greater value of x is 7.

Solve for $x$ . Enter the solutions from least to greatest. $\newline$ $\begin{array}{l} 2 x^{2}-16 x+14=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}$

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Solve for x x x. Enter the solutions from least to greatest.\newline2x2−16x+14=0 lesser x=□ greater x=□ \begin{array}{l} 2 x^{2}-16 x+14=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array} 2x2−16x+14=0 lesser x=□ greater x=□​

Solve for $x$ . Enter the solutions from least to greatest. $\newline$ $\begin{array}{l} 2 x^{2}-16 x+14=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}$