Solve for x. Enter the solutions from least to greatest. {:[(2x-1)(x+4)=0],[" lesser "x=◻],[" greater "x=◻]:}

Factorization: Factored polynomial: (2x-1)(x+4)=0 To find the roots of this polynomial, we need to set each factor equal to zero and solve for x.First Factor Solution: First factor: 2x - 1 = 0 To find the value of x, we add 1 to both sides of the equation. 2x - 1 + 1 = 0 + 1 2x = 1 Now, we divide both sides by 2 to solve for x. 2x / 2 = 1 / 2 x = 1/2Second Factor Solution: Second factor: x + 4 = 0 To find the value of x, we subtract 4 from both sides of the equation. x + 4 - 4 = 0 - 4 x = -4Final Solutions: We have found two solutions for x: x = 1/2 x = -4 Now we need to list the solutions from least to greatest. -4 < 1/2

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Math Problems

Algebra 2

Find the roots of factored polynomials

Full solution

Q. Solve for

x

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Enter the solutions from least to greatest.

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(2 x-1)(x+4)=0

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lesser

x=

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greater

x=

Factorization: Factored polynomial: $2x-1)(x+4)=0\ To find the roots of this polynomial, we need to set each factor equal to zero and solve for \$x$ .
First Factor Solution: First factor: $2x - 1 = 0$ $\newline$ To find the value of $x$ , we add $1$ to both sides of the equation. $\newline$ $2x - 1 + 1 = 0 + 1$ $\newline$ $2x = 1$ $\newline$ Now, we divide both sides by $2$ to solve for $x$ . $\newline$ $\frac{2x}{2} = \frac{1}{2}$ $\newline$ $x = \frac{1}{2}$
Second Factor Solution: Second factor: $x + 4 = 0$ $\newline$ To find the value of $x$ , we subtract $4$ from both sides of the equation. $\newline$ $x + 4 - 4 = 0 - 4$ $\newline$ $x = -4$
Final Solutions: We have found two solutions for $x$ : $x = \frac{1}{2}$ $x = -4$ Now we need to list the solutions from least to greatest.-4 < \frac{1}{2}