Solve for x. -8x+44 >= 60quad" AND "quad-4x+50 -2 (B) x <= -2 (C) x=-2 D There are no solutions (E) All values of x are solutions

Solve First Inequality: First, let's solve the inequality -8x + 44 ≥ 60. Subtract 44 from both sides to isolate the term with x. -8x + 44 - 44 ≥ 60 - 44 -8x ≥ 16 Now, divide both sides by -8 to solve for x. Remember that dividing by a negative number reverses the inequality sign. -8x / -8 ≤ 16 / -8 x ≤ -2Solve Second Inequality: Next, let's solve the inequality -4x + 50 8 / -4 x > -2Combine Inequalities: Now we have two inequalities to combine: x ≤ -2 from the first inequality, and x > -2 from the second inequality. However, these two inequalities contradict each other because there is no number that is both greater than and less than or equal to -2 at the same time. Therefore, there are no solutions that satisfy both inequalities simultaneously.

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Solve for
x.

-8x+44 >= 60quad" AND "quad-4x+50 < 58
Choose 1 answer:
(A)
x > -2
(B)
x <= -2
(C)
x=-2
D There are no solutions
(E) All values of
x are solutions

Solve for $x$ . $\newline$ -8 x+44 \geq 60 \quad \text { AND } \quad-4 x+50<58 $\newline$ Choose $1$ answer: $\newline$ (A) x>-2 $\newline$ (B) $x \leq-2$ $\newline$ (C) $x=-2$ $\newline$ (D) There are no solutions $\newline$ (E) All values of $x$ are solutions

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Math Problems

Algebra 1

Is (x, y) a solution to the system of linear inequalities?

Full solution

Q. Solve for

x

\newline

-8 x+44 \geq 60 \quad \text { AND } \quad-4 x+50<58

\newline

Choose

1

answer:

\newline

(A)

x>-2

\newline

(B)

x \leq-2

\newline

(C)

x=-2

\newline

(D) There are no solutions

\newline

(E) All values of

x

are solutions

Solve First Inequality: First, let's solve the inequality $-8x + 44 \geq 60$ . Subtract $44$ from both sides to isolate the term with $x$ . $-8x + 44 - 44 \geq 60 - 44$ $-8x \geq 16$ Now, divide both sides by $-8$ to solve for $x$ . Remember that dividing by a negative number reverses the inequality sign. $-8x / -8 \leq 16 / -8$ $x \leq -2$
Solve Second Inequality: Next, let's solve the inequality -4x + 50 < 58. Subtract $50$ from both sides to isolate the term with $x$ . -4x + 50 - 50 < 58 - 50 -4x < 8 Now, divide both sides by $-4$ to solve for $x$ . Again, remember that dividing by a negative number reverses the inequality sign. -4x / -4 > 8 / -4 x > -2
Combine Inequalities: Now we have two inequalities to combine: $\newline$ $x \leq -2$ from the first inequality, and $\newline$ x > -2 from the second inequality. $\newline$ However, these two inequalities contradict each other because there is no number that is both greater than and less than or equal to $-2$ at the same time. $\newline$ Therefore, there are no solutions that satisfy both inequalities simultaneously.