Solve for x. 4x-39 > -43quad AND quad8x+31 -1 (B) x -1 (D) There are no solutions (E) All values of x are solutions

Solve first inequality: Solve the first inequality 4x - 39 > -43. Add 39 to both sides to isolate the term with x. 4x - 39 + 39 > -43 + 39 4x > -4Isolate x term in first inequality: Divide both sides by 4 to solve for x. 4x / 4 > -4 / 4 x > -1Solve second inequality: Solve the second inequality 8x + 31 -1, and the second inequality gives us x -1 and x < -1, there are no values of x that satisfy both inequalities at the same time.

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Solve for
x.

4x-39 > -43quad AND
quad8x+31 < 23
Choose 1 answer:
(A)
x < -1 or
x > -1
(B)
x < -1
(C)
x > -1
(D) There are no solutions
(E) All values of
x are solutions

Solve for $x$ . $\newline$ 4 x-39>-43 \quad AND \quad 8 x+31<23 $\newline$ Choose $1$ answer: $\newline$ (A) x<-1 or x>-1 $\newline$ (B) x<-1 $\newline$ (C) x>-1 $\newline$ (D) There are no solutions $\newline$ (E) All values of $x$ are solutions

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Math Problems

Algebra 1

Solve a quadratic equation by factoring

Full solution

Q. Solve for

x

\newline

4 x-39>-43 \quad

AND

\quad 8 x+31<23

\newline

Choose

1

answer:

\newline

(A)

x<-1

x>-1

\newline

(B)

x<-1

\newline

(C)

x>-1

\newline

(D) There are no solutions

\newline

(E) All values of

x

are solutions

Solve first inequality: Solve the first inequality 4x - 39 > -43. $\newline$ Add $39$ to both sides to isolate the term with $x$ . $\newline$ 4x - 39 + 39 > -43 + 39 $\newline$ 4x > -4
Isolate $x$ term in first inequality: Divide both sides by $4$ to solve for $x$ .
\frac{4x}{4} > \frac{-4}{4}
x > -1
Solve second inequality: Solve the second inequality 8x + 31 < 23.
Subtract $31$ from both sides to isolate the term with $x$ .
8x + 31 - 31 < 23 - 31
8x < -8
Isolate $x$ term in second inequality: Divide both sides by $8$ to solve for $x$ .
\frac{8x}{8} < \frac{-8}{8}
x < -1
Combine solutions of both inequalities: Combine the solutions of both inequalities to find the common solution set. $\newline$ The first inequality gives us x > -1, and the second inequality gives us x < -1. $\newline$ Since there is no overlap between x > -1 and x < -1, there are no values of $x$ that satisfy both inequalities at the same time.