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Simon has 160 meters of fencing to build a rectangular garden.
The garden's area (in square meters) as a function of the garden's width 
x (in meters) is modeled by

A(x)=-x(x-80)
What width will produce the maximum garden area?
meters

Simon has 160160 meters of fencing to build a rectangular garden.\newlineThe garden's area (in square meters) as a function of the garden's width \newlinexx (in meters) is modeled by\newlineA(x)=x(x80)A(x)=-x(x-80)\newlineWhat width will produce the maximum garden area?\newlinemeters \text{meters}

Full solution

Q. Simon has 160160 meters of fencing to build a rectangular garden.\newlineThe garden's area (in square meters) as a function of the garden's width \newlinexx (in meters) is modeled by\newlineA(x)=x(x80)A(x)=-x(x-80)\newlineWhat width will produce the maximum garden area?\newlinemeters \text{meters}
  1. Problem description: The problem involves finding the maximum value of a quadratic function, which is given in the form A(x)=x(x80)A(x) = -x(x - 80). This is a parabola that opens downwards because the coefficient of the x2x^2 term is negative. The maximum value of this function occurs at the vertex of the parabola.
  2. Finding the x-coordinate of the vertex: To find the x-coordinate of the vertex, we use the formula b2a-\frac{b}{2a}, where the quadratic function is in the form ax2+bx+cax^2 + bx + c. In our function A(x)=x(x80)A(x) = -x(x - 80), a=1a = -1 and b=80b = 80.
  3. Calculating the x-coordinate: Plugging the values of aa and bb into the vertex formula, we get 8021=802=40-\frac{80}{2 \cdot -1} = \frac{-80}{-2} = 40. This means the x-coordinate of the vertex, which gives us the width that will produce the maximum garden area, is 4040 meters.
  4. Verification of calculation: To ensure there is no math error, we can check our calculation: 80-80 divided by 2-2 indeed equals 4040.

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