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Rui is a professional deep water free diver.
His altitude (in meters relative to sea level), 
x seconds after diving, is modeled by:

d(x)=(1)/(2)x^(2)-10 x
How many seconds after diving will Rui reach his lowest altitude?
seconds

Rui is a professional deep water free diver. His altitude (in meters relative to sea level), xx seconds after diving, is modeled by:\newlined(x)=12x210xd(x)=\frac{1}{2}x^{2}-10x\newlineHow many seconds after diving will Rui reach his lowest altitude?\newlineseconds\text{seconds}

Full solution

Q. Rui is a professional deep water free diver. His altitude (in meters relative to sea level), xx seconds after diving, is modeled by:\newlined(x)=12x210xd(x)=\frac{1}{2}x^{2}-10x\newlineHow many seconds after diving will Rui reach his lowest altitude?\newlineseconds\text{seconds}
  1. Identify Quadratic Equation: Identify the quadratic equation that models Rui's altitude.\newlineThe given equation is d(x)=(12)x210xd(x) = (\frac{1}{2})x^2 - 10x. This is a quadratic equation in the form of ax2+bx+cax^2 + bx + c, where a=12a = \frac{1}{2}, b=10b = -10, and c=0c = 0.
  2. Determine Vertex Time: Determine the xx-coordinate of the vertex of the parabola, which will give us the time at which Rui reaches his lowest altitude.\newlineThe xx-coordinate of the vertex of a parabola given by ax2+bx+cax^2 + bx + c is found using the formula x=b2ax = -\frac{b}{2a}. Here, a=12a = \frac{1}{2} and b=10b = -10.
  3. Calculate Vertex x-coordinate: Calculate the x-coordinate of the vertex using the values of aa and bb.x=(10)/(2(1/2))x = -(-10)/(2*(1/2))x=10/(2(1/2))x = 10/(2*(1/2))x=10/1x = 10/1x=10x = 10
  4. Interpret Result: Interpret the result.\newlineThe xx-coordinate of the vertex is 1010, which means that Rui will reach his lowest altitude 1010 seconds after diving.

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