Rewrite the equation by completing the square. {:[4x^(2)+28 x+49=0],[(x+◻)^(2)=◻]:}

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Rewrite the equation by completing the square.  {:[4x^(2)+28 x+49=0],[(x+◻)^(2)=◻]:}

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Identify quadratic equation and terms: Identify the given quadratic equation and its terms. The given equation is 4x^2 + 28x + 49 = 0. We need to complete the square for this equation.Factor out coefficient of x^2: Factor out the coefficient of x^2 from the first two terms. Since the coefficient of x^2 is 4, we factor it out from the first two terms to make the x^2 term a perfect square. 4(x^2 + 7x) + 49 = 0Find value to complete the square: Find the value to complete the square. To complete the square, we need to add and subtract the square of half the coefficient of x inside the parentheses. The coefficient of x is 7, so half of 7 is 3.5, and the square of 3.5 is 12.25. 4(x^2 + 7x + 12.25 - 12.25) + 49 = 0Add and subtract value inside parentheses: Add and subtract the value inside the parentheses and simplify. We add and subtract 12.25 inside the parentheses and factor the perfect square trinomial. 4((x + 3.5)^2 - 12.25) + 49 = 0Distribute and combine like terms: Distribute the 4 and combine like terms. Now we distribute the 4 into the parentheses and combine the constant terms. 4(x + 3.5)^2 - 49 + 49 = 0Simplify the equation: Simplify the equation. The -49 and +49 cancel each other out, leaving us with the completed square form of the equation. 4(x + 3.5)^2 = 0Write final completed square form: Write the final completed square form. The final completed square form of the equation is: (x + 3.5)^2 = 0

Rewrite the equation by completing the square. $\newline$ $4x^{2}+28x+49=0$ $\newline$ $(x+\square)^{2}=\square$

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Rewrite the equation by completing the square.\newline4x2+28x+49=04x^{2}+28x+49=04x2+28x+49=0\newline(x+□)2=□(x+\square)^{2}=\square(x+□)2=□

Rewrite the equation by completing the square. $\newline$ $4x^{2}+28x+49=0$ $\newline$ $(x+\square)^{2}=\square$