Nathaniel builds birds and birdhouses using Lego blocks. Let B represent the number of birds and H represent the number of birdhouses that Nathaniel can build with his Lego blocks. 43 B+215 H

Question

Nathaniel builds birds and birdhouses using Lego blocks. Let  B represent the number of birds and  H represent the number of birdhouses that Nathaniel can build with his Lego blocks.  43 B+215 H <= 3000 Nathaniel wants to build 50 birds using Lego blocks. How many birdhouses can he build at most with the remaining Lego blocks? Choose 1 answer: (A) Nathaniel can build at most 1 birdhouse. (B) Nathaniel can build at most 2 birdhouses. (c) Nathaniel can build at most 3 birdhouses. (D) Nathaniel can build at most 4 birdhouses.

Bytelearn · Accepted Answer

Understand the inequality: Understand the given inequality and what it represents. The inequality 43B + 215H ≤ 3000 tells us that the total number of Lego blocks used to build birds (B) and birdhouses (H) cannot exceed 3000. Each bird requires 43 blocks, and each birdhouse requires 215 blocks.Substitute number of birds: Substitute the number of birds Nathaniel wants to build into the inequality. Nathaniel wants to build 50 birds, so we substitute B with 50 in the inequality: 43(50) + 215H ≤ 3000Calculate blocks for birds: Calculate the number of Lego blocks used for 50 birds. 43(50) = 2150 So, Nathaniel will use 2150 blocks for the birds.Subtract blocks for birds: Subtract the number of blocks used for birds from the total limit to find out how many blocks are left for birdhouses. 3000 - 2150 = 850 Nathaniel has 850 blocks left for building birdhouses.Divide remaining blocks for birdhouses: Divide the remaining number of blocks by the number of blocks required for one birdhouse to find out the maximum number of birdhouses Nathaniel can build. 850 ÷ 215 = 3.95348837 Since Nathaniel cannot build a fraction of a birdhouse, he can build at most 3 birdhouses.

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