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Ming throws a stone off a bridge into a river below.
The stone's height (in meters above the water), 
x seconds after Ming threw it, is modeled by:

h(x)=-5(x-1)^(2)+45
What is the maximum height that the stone will reach?
meters

Ming throws a stone off a bridge into a river below.\newlineThe stone's height (in meters above the water), \newlinexx seconds after Ming threw it, is modeled by:\newlineh(x)=5(x1)2+45h(x)=-5(x-1)^{2}+45\newlineWhat is the maximum height that the stone will reach?\newlinemeters\text{meters}

Full solution

Q. Ming throws a stone off a bridge into a river below.\newlineThe stone's height (in meters above the water), \newlinexx seconds after Ming threw it, is modeled by:\newlineh(x)=5(x1)2+45h(x)=-5(x-1)^{2}+45\newlineWhat is the maximum height that the stone will reach?\newlinemeters\text{meters}
  1. Identify Function Type: Identify the type of function and its properties.\newlineThe function h(x)=5(x1)2+45h(x) = -5(x-1)^2 + 45 is a quadratic function in the form of h(x)=a(xh)2+kh(x) = a(x-h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. Since the coefficient of the squared term is negative (a=5)(a = -5), the parabola opens downwards, which means the vertex is the maximum point of the function.
  2. Determine Vertex: Determine the vertex of the parabola.\newlineThe vertex form of the quadratic function gives us the vertex directly. The vertex (h,k)(h, k) of the function h(x)=5(x1)2+45h(x) = -5(x-1)^2 + 45 is (1,45)(1, 45). This means the maximum height of the stone is 4545 meters, which occurs at x=1x = 1 second.

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