Q. Let m=5x−2. Which equation is equivalent to (5x−2)2+35x−14=−12 in terms of m? Choose 1 answer:(A) m2−7m−2=0(B) m2−7m+12=0(C) m2+7m−2=0(D) m2+7m+12=0
Expand (5x−2)2: We are given that m=5x−2. We need to express the equation (5x−2)2+35x−14=−12 in terms of m.First, let's expand (5x−2)2.(5x−2)2=(5x−2)(5x−2)=25x2−10x−10x+4=25x2−20x+4
Substitute expanded form into equation: Now, let's substitute the expanded form of (5x−2)2 into the original equation.25x2−20x+4+35x−14=−12
Combine like terms: Combine like terms in the equation. 25x2+15x−10=−12
Set equation to zero: Add 12 to both sides to set the equation to zero.25x2+15x−10+12=025x2+15x+2=0
Substitute m back into equation: Now, we need to express this equation in terms of m. Recall that m=5x−2.Let's substitute 5x−2 back in for m.m2+35x−14=−12
Solve for x: We need to express 35x in terms of m. Since m=5x−2, we can solve for x: 5x=m+2x=5m+2
Substitute x back into equation: Substitute x back into the equation in terms of m.m2+35(5m+2)−14=−12
Distribute 35 inside parentheses: Distribute the 35 inside the parentheses.m2+7(m+2)−14=−12
Expand the equation: Expand the equation. m2+7m+14−14=−12
Combine like terms: Combine like terms. m2+7m=−12
Set equation to zero: Add 12 to both sides to set the equation to zero.m2+7m+12=0
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