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Lúcia posted a video of her cat playing on the piano. She found that the following expression modeled the total number of people who had viewed her video 
t days after she posted it.

18*16^(0.0125 t)
After how many days did the total number of people viewing the video double from the original number of people?
(Round your answer to the nearest day.)

Lúcia posted a video of her cat playing on the piano. She found that the following expression modeled the total number of people who had viewed her video t t days after she posted it.\newline18160.0125t 18 \cdot 16^{0.0125 t} \newlineAfter how many days did the total number of people viewing the video double from the original number of people?\newline(Round your answer to the nearest day.)

Full solution

Q. Lúcia posted a video of her cat playing on the piano. She found that the following expression modeled the total number of people who had viewed her video t t days after she posted it.\newline18160.0125t 18 \cdot 16^{0.0125 t} \newlineAfter how many days did the total number of people viewing the video double from the original number of people?\newline(Round your answer to the nearest day.)
  1. Denote original number of viewers: Let's denote the original number of people who viewed the video as VV. According to the given expression, V=18V = 18. We want to find the time tt when the number of viewers is double the original number, which means we want to find tt when the number of viewers is 2V=2×18=362V = 2 \times 18 = 36. The expression modeling the total number of people who have viewed the video tt days after it was posted is:\newline18×160.0125t18 \times 16^{0.0125t}\newlineWe need to set this equal to 2V2V and solve for tt.
  2. Set up equation for doubling viewers: Set up the equation to find when the number of viewers doubles:\newline36=18×160.0125t36 = 18 \times 16^{0.0125t}\newlineDivide both sides by 1818 to isolate the exponential term:\newline2=160.0125t2 = 16^{0.0125t}
  3. Use logarithms to solve: To solve for tt, we need to use logarithms. We can use the natural logarithm (ln\ln) or the common logarithm (log\log). Let's use the natural logarithm:\newlineln(2)=ln(160.0125t)\ln(2) = \ln(16^{0.0125t})\newlineUsing the property of logarithms that ln(ab)=bln(a)\ln(a^b) = b \cdot \ln(a), we can rewrite the right side of the equation:\newlineln(2)=0.0125tln(16)\ln(2) = 0.0125t \cdot \ln(16)
  4. Calculate value of t: Now, we need to solve for t by dividing both sides of the equation by (0.0125ln(16))(0.0125 * \ln(16)):\newlinet=ln(2)(0.0125ln(16))t = \frac{\ln(2)}{(0.0125 * \ln(16))}\newlineCalculate the value of t using a calculator:\newlinetln(2)(0.0125ln(16))t \approx \frac{\ln(2)}{(0.0125 * \ln(16))}\newlinet0.69314718056(0.01252.77258872224)t \approx \frac{0.69314718056}{(0.0125 * 2.77258872224)}\newlinet0.693147180560.03465735903t \approx \frac{0.69314718056}{0.03465735903}\newlinet20t \approx 20 days

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