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In physics, work is defined as 
F*D where 
F is the force applied over a distance of 
D.
A box is dragged across 20 meters with a force of 60 Newtons, which are 
(kg*m)/(s^(2)).
What calculation will give us the work done, in Joules (which are 
{:(kg*m^(2))/(s^(2))) ?
Choose 1 answer:
(A) 
20*60
(B) 
20*1000*60
(c) 
(20)/(1000)*60
(D) 
(20)/(60)

In physics, work is defined as \newlineFDF \cdot D where \newlineFF is the force applied over a distance of \newlineDD.\newlineA box is dragged across 2020 meters with a force of 6060 Newtons, which are \newline(kgms2)\left(\frac{\text{kg} \cdot \text{m}}{\text{s}^{2}}\right).\newlineWhat calculation will give us the work done, in Joules (which are \newline(kgm2s2)\left(\frac{\text{kg} \cdot \text{m}^{2}}{\text{s}^{2}}\right) ?\newlineChoose 11 answer:\newline(A) 206020 \cdot 60\newline(B) 2010006020 \cdot 1000 \cdot 60\newline(C) 20100060\frac{20}{1000} \cdot 60\newline(D) FF00

Full solution

Q. In physics, work is defined as \newlineFDF \cdot D where \newlineFF is the force applied over a distance of \newlineDD.\newlineA box is dragged across 2020 meters with a force of 6060 Newtons, which are \newline(kgms2)\left(\frac{\text{kg} \cdot \text{m}}{\text{s}^{2}}\right).\newlineWhat calculation will give us the work done, in Joules (which are \newline(kgm2s2)\left(\frac{\text{kg} \cdot \text{m}^{2}}{\text{s}^{2}}\right) ?\newlineChoose 11 answer:\newline(A) 206020 \cdot 60\newline(B) 2010006020 \cdot 1000 \cdot 60\newline(C) 20100060\frac{20}{1000} \cdot 60\newline(D) FF00
  1. Understand Work Formula: Understand the formula for work. Work (WW) is calculated by multiplying the force (FF) applied to an object by the distance (DD) over which the force is applied. The formula is W=F×DW = F \times D.
  2. Identify Force and Distance: Identify the values for force and distance.\newlineIn this problem, the force applied is 6060 Newtons and the distance is 2020 meters.
  3. Apply Work Formula: Apply the values to the work formula.\newlineUsing the formula W=F×DW = F \times D, we substitute the given values to get W=60N×20mW = 60 \, \text{N} \times 20 \, \text{m}.
  4. Perform Multiplication: Perform the multiplication to find the work done. \newlineW=60N×20m=1200NmW = 60 \, \text{N} \times 20 \, \text{m} = 1200 \, \text{N} \cdot \text{m}. \newlineSince 1Joule1 \, \text{Joule} is equivalent to 1Newton-meter1 \, \text{Newton-meter}, the work done is 1200Joules1200 \, \text{Joules}.
  5. Match Calculation with Choices: Match the calculation with the given choices.\newlineThe correct calculation that matches our result is (A)20×60(A) 20\times60.

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