If y=(x-2)(x-1)(2x^(2)+3)+4 what is the value of y when x=1 ?

Given Function and Task: We are given the function y=(x-2)(x-1)(2x^(2)+3)+4 and asked to find the value of y when x=1. We will substitute x=1 into the function and simplify.Substitute x=1: Substitute x=1 into the function: y=(1-2)(1-1)(2(1)^(2)+3)+4.Simplify Inside Parentheses: Simplify the terms inside the parentheses: y=(-1)(0)(2*1+3)+4.Perform Multiplication: Further simplify the expression by performing the multiplication: y=(-1)(0)(2+3)+4.Final Result: Since any number multiplied by zero is zero, the whole term (-1)(0)(5) becomes zero: y=0+4.Add 4 to the result: y=4.

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If

y=(x-2)(x-1)(2x^(2)+3)+4
what is the value of
y when
x=1 ?

If $y=(x-2)(x-1)\left(2 x^{2}+3\right)+4$ what is the value of $y$ when $x=1$ ?

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Algebra 2

Evaluate exponential functions

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Q. If

y=(x-2)(x-1)\left(2 x^{2}+3\right)+4

what is the value of

y

when

x=1

Given Function and Task: We are given the function $y=(x-2)(x-1)(2x^{2}+3)+4$ and asked to find the value of $y$ when $x=1$ . We will substitute $x=1$ into the function and simplify.
Substitute $x=1$ : Substitute $x=1$ into the function: $y=(1-2)(1-1)(2(1)^{2}+3)+4$ .
Simplify Inside Parentheses: Simplify the terms inside the parentheses: $y=(-1)(0)(2\times1+3)+4$ .
Perform Multiplication: Further simplify the expression by performing the multiplication: $y=(-1)(0)(2+3)+4$ .
Final Result: Since any number multiplied by zero is zero, the whole term $(-1)(0)(5)$ becomes zero: $y=0+4$ .
Final Result: Since any number multiplied by zero is zero, the whole term $(-1)(0)(5)$ becomes zero: $y=0+4$ . Add $4$ to the result: $y=4$ .