If f(x)=(2x-1)(x-6)(3x+1)", " what is the value of f((1)/(2)) ?

Given Function: We are given the function f(x)=(2x-1)(x-6)(3x+1) and we need to find the value of f((1)/(2)). To do this, we will substitute x with (1)/(2) in the function and simplify.Substitute in First Term: First, substitute (1)/(2) for x in the first term (2x-1): (2*(1)/(2) - 1) = (1 - 1) = 0.Substitute in Second Term: Next, substitute (1)/(2) for x in the second term (x-6): ((1)/(2) - 6) = -5.5 or -11/2.Substitute in Third Term: Then, substitute (1)/(2) for x in the third term (3x+1): (3*(1)/(2) + 1) = (1.5 + 1) = 2.5 or 5/2.Multiply Results: Now, multiply the results of the three terms together to find f((1)/(2)): 0 * (-11/2) * (5/2) = 0.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

If

f(x)=(2x-1)(x-6)(3x+1)", "
what is the value of
f((1)/(2)) ?

If $f(x)=(2 x-1)(x-6)(3 x+1)$ , what is the value of $f\left(\frac{1}{2}\right)$ ?

View step-by-step help

Home

Math Problems

Grade 8

Solve multi-step equations with fractional coefficients

Full solution

Q. If

f(x)=(2 x-1)(x-6)(3 x+1)

, what is the value of

f\left(\frac{1}{2}\right)

Given Function: We are given the function $f(x)=(2x-1)(x-6)(3x+1)$ and we need to find the value of $f\left(\frac{1}{2}\right)$ . To do this, we will substitute $x$ with $\frac{1}{2}$ in the function and simplify.
Substitute in First Term: First, substitute $(\frac{1}{2})$ for $x$ in the first term $(2x-1)$ : $\newline$ $= 2 \cdot (\frac{1}{2}) - 1$ $\newline$ $= 1 - 1$ $\newline$ $= 0$
Substitute in Second Term: Next, substitute $\frac{1}{2}$ for $x$ in the second term $(x-6)$ : $\newline$ $= \frac{1}{2} - 6$ $\newline$ $= -5.5$ or $-\frac{11}{2}$
Substitute in Third Term: Then, substitute $\frac{1}{2}$ for $x$ in the third term $(3x+1)$ : $\newline$ $= 3\cdot\frac{1}{2} + 1$ $\newline$ $= 1.5 + 1$ $\newline$ $= 2.5$ or $\frac{5}{2}$
Multiply Results: Now, multiply the results of the three terms together to find $f\left(\frac{1}{2}\right)$ : $\newline$ $f(x)=(2x-1)(x-6)(3x+1)$ $\newline$ $f\left(\frac{1}{2}\right) = 0 \times \left(-\frac{11}{2}\right) \times \left(\frac{5}{2}\right)$ $\newline$ $f\left(\frac{1}{2}\right) = 0$