If -8-8y=6-2y, what is the value of y ? Choose 1 answer: (A) y=-(3)/(7) (B) y=(3)/(7) (c) y=(7)/(3) (D) y=-(7)/(3)

Isolate variable terms: Isolate the variable terms on one side of the equation. We will move the terms containing y to one side and the constant terms to the other side. To do this, we will add 8y to both sides of the equation to move the y terms to the right side and add 8 to both sides to move the constant terms to the left side. -8 - 8y + 8y = 6 - 2y + 8y -8 = 6 + 6yMove y terms to right side: Now, we will subtract 6 from both sides to isolate the term with y on the right side. -8 - 6 = 6 + 6y - 6 -14 = 6yMove constant terms to left side: Divide both sides by 6 to solve for y. -14 / 6 = 6y / 6 y = -14 / 6Subtract 6 from both sides: Simplify the fraction -14 / 6 to its simplest form. y = -7 / 3

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

If
-8-8y=6-2y, what is the value of
y ?
Choose 1 answer:
(A)
y=-(3)/(7)
(B)
y=(3)/(7)
(c)
y=(7)/(3)
(D)
y=-(7)/(3)

If $-8-8y=6-2y$ , what is the value of $y$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $y=-\frac{3}{7}$ $\newline$ (B) $y=\frac{3}{7}$ $\newline$ (C) $y=\frac{7}{3}$ $\newline$ (D) $y=-\frac{7}{3}$

View step-by-step help

Home

Math Problems

Grade 8

Solve multi-step equations with fractional coefficients

Full solution

Q. If

-8-8y=6-2y

, what is the value of

y

\newline

Choose

1

answer:

\newline

(A)

y=-\frac{3}{7}

\newline

(B)

y=\frac{3}{7}

\newline

(C)

y=\frac{7}{3}

\newline

(D)

y=-\frac{7}{3}

Isolate variable terms: Isolate the variable terms on one side of the equation. $\newline$ We will move the terms containing $y$ to one side and the constant terms to the other side. To do this, we will add $8y$ to both sides of the equation to move the $y$ terms to the right side and add $8$ to both sides to move the constant terms to the left side. $\newline$ $-8 - 8y + 8y = 6 - 2y + 8y$ $\newline$ $-8 = 6 + 6y$
Move y terms to right side: Now, we will subtract $6$ from both sides to isolate the term with $y$ on the right side. $-8 - 6 = 6 + 6y - 6$ $-14 = 6y$
Move constant terms to left side: Divide both sides by $6$ to solve for $y$ .
$-\frac{14}{6} = \frac{6y}{6}$
$y = -\frac{14}{6}$
Subtract $6$ from both sides: Simplify the fraction $-\frac{14}{6}$ to its simplest form. $\newline$ y = $-\frac{7}{3}$