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Let’s check out your problem:

If 
-24=3(1+r), what is the value of 
7(1+r) ?
Choose 1 answer:
(A) -56
(B) -24
(C) -9
(D) -8

If 24=3(1+r) -24=3(1+r) , what is the value of 7(1+r) 7(1+r) ?\newlineChoose 11 answer:\newline(A) 56-56\newline(B) 24-24\newline(C) 9-9\newline(D) 8-8

Full solution

Q. If 24=3(1+r) -24=3(1+r) , what is the value of 7(1+r) 7(1+r) ?\newlineChoose 11 answer:\newline(A) 56-56\newline(B) 24-24\newline(C) 9-9\newline(D) 8-8
  1. Find rr: Given the equation 24=3(1+r)-24 = 3(1 + r), we need to find the value of rr first.\newlineSolve for rr by dividing both sides by 33.\newline24/3=3(1+r)/3-24 / 3 = 3(1 + r) / 3\newline8=1+r-8 = 1 + r
  2. Isolate rr: Now, subtract 11 from both sides to isolate rr.\newline81=1+r1-8 - 1 = 1 + r - 1\newline9=r-9 = r
  3. Substitute rr: With the value of rr found, we can now find the value of 7(1+r)7(1 + r). Substitute 9-9 for rr in 7(1+r)7(1 + r). 7(19)=7(8)7(1 - 9) = 7(-8)
  4. Multiply to find value: Now, multiply 77 by 8-8 to find the value of 7(1+r)7(1 + r). \newline7×8=567 \times -8 = -56