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Guillermo is a professional deep water free diver.
His altitude (in meters relative to sea level), 
x seconds after diving, is modeled by

g(x)=(1)/(20)x(x-100)
What is the lowest altitude Guillermo will reach?
meters relative to sea level

Guillermo is a professional deep water free diver. His altitude (in meters relative to sea level), xx seconds after diving, is modeled by\newlineg(x)=120x(x100)g(x)=\frac{1}{20}x(x-100)\newlineWhat is the lowest altitude Guillermo will reach? meters relative to sea level

Full solution

Q. Guillermo is a professional deep water free diver. His altitude (in meters relative to sea level), xx seconds after diving, is modeled by\newlineg(x)=120x(x100)g(x)=\frac{1}{20}x(x-100)\newlineWhat is the lowest altitude Guillermo will reach? meters relative to sea level
  1. Find Minimum Value: To find the lowest altitude Guillermo will reach, we need to find the minimum value of the function g(x)=(120)x(x100)g(x)=(\frac{1}{20})x(x-100). This is a quadratic function, which is parabolic in shape and opens upwards since the coefficient of x2x^2 is positive. The minimum value of the function occurs at the vertex of the parabola.
  2. Calculate Vertex: The vertex of a parabola given by the function f(x)=ax2+bx+cf(x) = ax^2 + bx + c is at the point (h,k)(h, k), where h=b2ah = -\frac{b}{2a}. In the case of g(x)g(x), we can rewrite the function in the form of ax2+bx+cax^2 + bx + c to find aa and bb.g(x)=120x(x100)=120x2120100x=120x25xg(x) = \frac{1}{20}x(x-100) = \frac{1}{20}x^2 - \frac{1}{20}\cdot100x = \frac{1}{20}x^2 - 5x.Here, a=120a = \frac{1}{20} and b=5b = -5.
  3. Find x-coordinate: Now we calculate the x-coordinate of the vertex using the formula h=b2ah = -\frac{b}{2a}.h=52(120)=5110=510=50h = -\frac{-5}{2*(\frac{1}{20})} = \frac{5}{\frac{1}{10}} = 5*10 = 50.
  4. Find y-coordinate: The xx-coordinate of the vertex is 5050. To find the yy-coordinate, which is the minimum altitude, we substitute x=50x = 50 into the function g(x)g(x). \newlineg(50)=(120)50(50100)=(120)50(50)=125g(50) = \left(\frac{1}{20}\right)*50*(50-100) = \left(\frac{1}{20}\right)*50*(-50) = -125.
  5. Final Altitude: The lowest altitude Guillermo will reach is 125-125 meters relative to sea level.

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