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For a given input value b, the function g outputs a value a to satisfy the following equation. a-7=3(b+2) Write a formula for g(b) in terms of b. g(b)=

For a given input value b b , the function g g outputs a value a a to satisfy the following equation.\newlinea−7=3(b+2) a-7=3(b+2) \newlineWrite a formula for g(b) g(b) in terms of b b .\newlineg(b)= g(b)=

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Q. For a given input value b b , the function g g outputs a value a a to satisfy the following equation.\newlinea−7=3(b+2) a-7=3(b+2) \newlineWrite a formula for g(b) g(b) in terms of b b .\newlineg(b)= g(b)=
  1. Given equation: We are given the equation a−7=3(b+2)a - 7 = 3(b + 2). To find the formula for g(b)g(b), we need to express aa in terms of bb.
  2. Distributing the 33: First, distribute the 33 on the right side of the equation to both terms inside the parentheses: 3(b+2)=3b+63(b + 2) = 3b + 6.
  3. Isolating aa: Now, we have the equation a−7=3b+6a - 7 = 3b + 6. To solve for aa, we need to isolate it on one side of the equation. We do this by adding 77 to both sides of the equation.
  4. Simplifying the equation: Adding 77 to both sides gives us a=3b+6+7a = 3b + 6 + 7.
  5. Formula for g(b): Simplify the right side of the equation by combining like terms: 3b+6+7=3b+133b + 6 + 7 = 3b + 13.
  6. Formula for g(b): Simplify the right side of the equation by combining like terms: 3b+6+7=3b+133b + 6 + 7 = 3b + 13.Now we have the formula for aa in terms of bb, which is a=3b+13a = 3b + 13. Since gg outputs a value aa for a given input value bb, we can write the formula for g(b)g(b) as g(b)=3b+13g(b) = 3b + 13.

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