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For a given input value 
a, the function 
f outputs a value 
b to satisfy the following equation.

-3a+6b=a+4b
Write a formula for 
f(a) in terms of 
a.

f(a)=

For a given input value aa, the function ff outputs a value bb to satisfy the following equation.\newline3a+6b=a+4b-3a+6b=a+4b\newlineWrite a formula for f(a)f(a) in terms of aa.\newlinef(a)=f(a)=

Full solution

Q. For a given input value aa, the function ff outputs a value bb to satisfy the following equation.\newline3a+6b=a+4b-3a+6b=a+4b\newlineWrite a formula for f(a)f(a) in terms of aa.\newlinef(a)=f(a)=
  1. Combine like terms: Combine like terms by moving all terms involving aa to one side and all terms involving bb to the other side.\newline3a+6b=a+4b-3a + 6b = a + 4b\newlineAdd 3a3a to both sides and subtract 4b4b from both sides to isolate the terms with bb on one side.\newline3a+3a+6b4b=a+3a+4b4b-3a + 3a + 6b - 4b = a + 3a + 4b - 4b\newlineSimplify the equation.\newline6b4b=4a6b - 4b = 4a\newline2b=4a2b = 4a
  2. Isolate terms with bb: Solve for bb in terms of aa.\newlineDivide both sides of the equation by 22 to solve for bb.\newline2b2=4a2\frac{2b}{2} = \frac{4a}{2}\newlineSimplify the equation.\newlineb=2ab = 2a
  3. Simplify the equation: Write the function f(a)f(a) in terms of aa.\newlineSince bb is the output of the function ff for the input aa, we can write bb as f(a)f(a).\newlinef(a)=2af(a) = 2a

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