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Find the zeros of the function. Enter the solutions from least to greatest.

f(x)=(x+3)^(2)-4
lesser
x=
greater
x=

Find the zeros of the function. Enter the solutions from least to greatest. $\newline$ $f(x)=(x+3)^{2}-4$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Evaluate exponential functions

Full solution

Q. Find the zeros of the function. Enter the solutions from least to greatest.

\newline

f(x)=(x+3)^{2}-4

\newline

lesser

x=

\newline

greater

x=

Find zeros of the function: Set the function equal to zero to find its zeros. $\newline$ $f(x) = (x+3)^2 - 4 = 0$
Solve the equation: Solve the equation $(x+3)^2 - 4 = 0$ by moving $4$ to the other side. $\newline$ $(x+3)^2 = 4$
Take the square root: Take the square root of both sides of the equation to solve for x. $\newline$ $\sqrt{(x+3)^2} = \pm\sqrt{4}$ $\newline$ $x+3 = \pm2$
Solve for x (positive case): Solve for x by subtracting $3$ from both sides of the equation for both the positive and negative cases. $\newline$ For the positive case: $\newline$ $x + 3 = 2$ $\newline$ $x = 2 - 3$ $\newline$ $x = -1$ $\newline$ For the negative case: $\newline$ $x + 3 = -2$ $\newline$ $x = -2 - 3$ $\newline$ $x = -5$

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