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Find the zeros of the function. Enter the solutions from least to greatest.

f(x)=(x+2)^(2)-16
lesser
x=
greater
x=

Find the zeros of the function. Enter the solutions from least to greatest. $\newline$ $f(x)=(x+2)^{2}-16$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Evaluate exponential functions

Full solution

Q. Find the zeros of the function. Enter the solutions from least to greatest.

\newline

f(x)=(x+2)^{2}-16

\newline

lesser

x=

\newline

greater

x=

Find Zeros of the Function: Set the function equal to zero to find its zeros. $\newline$ $f(x) = (x+2)^2 - 16 = 0$
Solve the Equation: Solve the equation $(x+2)^2 - 16 = 0$ by moving $16$ to the other side of the equation. $\newline$ $(x+2)^2 = 16$
Take the Square Root: Take the square root of both sides of the equation to solve for x. $\newline$ $\sqrt{(x+2)^2} = \pm\sqrt{16}$ $\newline$ $x + 2 = \pm4$
Solve for x: Solve for x by subtracting $2$ from both sides of the equation for both the positive and negative cases. $\newline$ For the positive case: $\newline$ $x + 2 = 4$ $\newline$ $x = 4 - 2$ $\newline$ $x = 2$ $\newline$ For the negative case: $\newline$ $x + 2 = -4$ $\newline$ $x = -4 - 2$ $\newline$ $x = -6$

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