Find the zeros of the function. Enter the solutions from least to greatest. {:[g(x)=(-5x-1)(2x+8)],[" lesser "x=◻],[" greater "x=◻]:}

Factored function: Factored function: g(x) = (-5x - 1)(2x + 8) To find the zeros of the function, we set g(x) equal to zero. 0 = (-5x - 1)(2x + 8)First zero: First zero: Solve -5x - 1 = 0 Add 1 to both sides: -5x - 1 + 1 = 0 + 1 -5x = 1 Now, divide by -5: x = 1 / -5 x = -1/5Second zero: Second zero: Solve 2x + 8 = 0 Subtract 8 from both sides: 2x + 8 - 8 = 0 - 8 2x = -8 Now, divide by 2: x = -8 / 2 x = -4Zeros of the function: We have found the zeros of the function: x = -1/5 (lesser zero) x = -4 (greater zero) List the solutions from least to greatest: x = -4, -1/5

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Find the zeros of the function. Enter the solutions from least to greatest.

{:[g(x)=(-5x-1)(2x+8)],[" lesser "x=◻],[" greater "x=◻]:}

Find the zeros of the function. Enter the solutions from least to greatest. $\newline$ $g(x) = (-5x - 1)(2x + 8)$ , $\text{lesser } x = \square$ , $\text{greater } x = \square$

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Algebra 2

Find the roots of factored polynomials

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Q. Find the zeros of the function. Enter the solutions from least to greatest.

\newline

g(x) = (-5x - 1)(2x + 8)

\text{lesser } x = \square

\text{greater } x = \square

Factored function: Factored function: $g(x) = (-5x - 1)(2x + 8)$ $\newline$ To find the zeros of the function, we set $g(x)$ equal to zero. $\newline$ $0 = (-5x - 1)(2x + 8)$
First zero: First zero: Solve $-5x - 1 = 0$
Add $1$ to both sides:
$-5x - 1 + 1 = 0 + 1$
$-5x = 1$
Now, divide by $-5$ :
$x = \frac{1}{-5}$
$x = -\frac{1}{5}$
Second zero: Second zero: Solve $2x + 8 = 0$
Subtract $8$ from both sides:
$2x + 8 - 8 = 0 - 8$
$2x = -8$
Now, divide by $2$ :
$x = \frac{-8}{2}$
$x = -4$
Zeros of the function: We have found the zeros of the function: $x = -\frac{1}{5}$ (lesser zero) $x = -4$ (greater zero) List the solutions from least to greatest: $x = -4, -\frac{1}{5}$