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Find the zeros of the function. Enter the solutions from least to greatest.

f(x)=(x+8)^(2)-1
lesser
x=
greater
x=

Find the zeros of the function. Enter the solutions from least to greatest. $\newline$ $f(x)=(x+8)^{2}-1$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Evaluate exponential functions

Full solution

Q. Find the zeros of the function. Enter the solutions from least to greatest.

\newline

f(x)=(x+8)^{2}-1

\newline

lesser

x=

\newline

greater

x=

Find zeros of the function: Set the function equal to zero to find its zeros. $f(x) = (x+8)^2 - 1 = 0$
Isolate the squared term: Add $1$ to both sides of the equation to isolate the squared term. $\newline$ $(x+8)^2 - 1 + 1 = 0 + 1$ $\newline$ $(x+8)^2 = 1$
Take the square root: Take the square root of both sides of the equation to solve for $x$ . $\sqrt{(x+8)^2} = \pm\sqrt{1}$ $x+8 = \pm1$
Solve for x (positive case): Solve for x by subtracting $8$ from both sides of the equation for both positive and negative cases. $\newline$ For the positive case: $\newline$ $x + 8 - 8 = 1 - 8$ $\newline$ $x = -7$ $\newline$ For the negative case: $\newline$ $x + 8 - 8 = -1 - 8$ $\newline$ $x = -9$

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