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Find the zeros of the function. Enter the solutions from least to greatest.

f(x)=(x+2)^(2)-64
lesser
x=
greater
x=

Find the zeros of the function. Enter the solutions from least to greatest. $\newline$ $f(x)=(x+2)^{2}-64$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Solve exponential equations by rewriting the base

Full solution

Q. Find the zeros of the function. Enter the solutions from least to greatest.

\newline

f(x)=(x+2)^{2}-64

\newline

lesser

x=

\newline

greater

x=

Find zeros of the function: Set the function equal to zero to find its zeros. $\newline$ $f(x) = (x+2)^2 - 64 = 0$
Isolate the squared term: Add $64$ to both sides of the equation to isolate the squared term. $\newline$ $(x+2)^2 = 64$
Solve for $x+2$ : Take the square root of both sides of the equation to solve for $x+2$ . $\newline$ $x+2 = \pm\sqrt{64}$
Simplify the square root: Simplify the square root of $64$ , which is $8$ . $\newline$ $x+2 = \pm 8$
Solve for x: Solve for x by subtracting $2$ from both sides of the equation for both the positive and negative cases. $\newline$ For the positive case: $x = 8 - 2$ $\newline$ For the negative case: $x = -8 - 2$
Calculate the values for x: Calculate the values for x. $\newline$ For the positive case: $x = 6$ $\newline$ For the negative case: $x = -10$

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