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Find the zeros of the function. Enter the solutions from least to greatest.

f(x)=(x-4)^(2)-16
lesser
x=
greater
x=

Find the zeros of the function. Enter the solutions from least to greatest. $\newline$ $f(x)=(x-4)^{2}-16$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Evaluate exponential functions

Full solution

Q. Find the zeros of the function. Enter the solutions from least to greatest.

\newline

f(x)=(x-4)^{2}-16

\newline

lesser

x=

\newline

greater

x=

Find Zeros of the Function: Set the function equal to zero to find its zeros. $\newline$ $f(x) = (x-4)^2 - 16 = 0$
Isolate the Squared Term: Add $16$ to both sides of the equation to isolate the squared term. $\newline$ $(x-4)^2 = 16$
Solve for x: Take the square root of both sides of the equation to solve for x. $\newline$ $\sqrt{(x-4)^2} = \pm\sqrt{16}$ $\newline$ $x - 4 = \pm 4$
Determine the Solutions: Solve for x by adding $4$ to both sides of each equation. $\newline$ For the positive root: $\newline$ $x - 4 + 4 = 4 + 4$ $\newline$ $x = 8$ $\newline$ For the negative root: $\newline$ $x - 4 + 4 = -4 + 4$ $\newline$ $x = 0$
List the Solutions: List the solutions from least to greatest. $\newline$ lesser $x = 0$ $\newline$ greater $x = 8$

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