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Find the zeros of the function. Enter the solutions from least to greatest.

f(x)=(x-8)^(2)-9
lesser
x=
greater
x=

Find the zeros of the function. Enter the solutions from least to greatest. $\newline$ $f(x)=(x-8)^{2}-9$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Evaluate exponential functions

Full solution

Q. Find the zeros of the function. Enter the solutions from least to greatest.

\newline

f(x)=(x-8)^{2}-9

\newline

lesser

x=

\newline

greater

x=

Find Zeros: Set the function equal to zero to find its zeros. $f(x) = (x-8)^2 - 9 = 0$
Isolate Squared Term: Add $9$ to both sides of the equation to isolate the squared term. $\newline$ $(x-8)^2 = 9$
Take Square Root: Take the square root of both sides of the equation to solve for $x$ . $\sqrt{(x-8)^2} = \pm\sqrt{9}$ $x - 8 = \pm3$
Solve for x: Solve for x by adding $8$ to both sides of each equation. $\newline$ For the positive root: $\newline$ $x - 8 + 8 = 3 + 8$ $\newline$ $x = 11$ $\newline$ For the negative root: $\newline$ $x - 8 + 8 = -3 + 8$ $\newline$ $x = 5$

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