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Your answer should be a polynomial in standard form.

(-a+1)(5a+6)=

Expand.\newlineYour answer should be a polynomial in standard form.\newline(a+1)(5a+6)=(-a+1)(5a+6)=

Full solution

Q. Expand.\newlineYour answer should be a polynomial in standard form.\newline(a+1)(5a+6)=(-a+1)(5a+6)=
  1. Multiplying terms inside parentheses: Now, we will multiply each term inside the parentheses by the term outside.\newlinea(5a)=5a2-a(5a) = -5a^2 (Multiplying a-a with 5a5a)\newlinea(6)=6a-a(6) = -6a (Multiplying a-a with 66)\newline1(5a)=5a1(5a) = 5a (Multiplying 11 with 5a5a)\newline1(6)=61(6) = 6 (Multiplying 11 with 66)
  2. Combining like terms: Next, we will combine the like terms from the multiplication results. 5a26a+5a+6-5a^2 - 6a + 5a + 6
  3. Writing in standard form: Combining the like terms 6a-6a and 5a5a gives us 1a-1a, or simply a-a.\newline5a26a+5a+6=5a2a+6-5a^2 - 6a + 5a + 6 = -5a^2 - a + 6
  4. Final answer: The expression is now fully expanded and simplified. We write it in standard form, which means the terms are in descending order of the exponents.\newlineThe final answer is 5a2a+6-5a^2 - a + 6.

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