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Expand.
Your answer should be a polynomial in standard form.

(9b-1)(9b+1)=

Expand.\newlineYour answer should be a polynomial in standard form.\newline(9b1)(9b+1)=(9b-1)(9b+1)=

Full solution

Q. Expand.\newlineYour answer should be a polynomial in standard form.\newline(9b1)(9b+1)=(9b-1)(9b+1)=
  1. Recognize the pattern: Recognize the pattern in the expression (9b1)(9b+1)(9b-1)(9b+1).\newlineThis expression is a difference of squares, which follows the pattern (ab)(a+b)=a2b2(a-b)(a+b) = a^2 - b^2.
  2. Apply the difference of squares formula: Apply the difference of squares formula.\newlineHere, aa is 9b9b and bb is 11. So, we have:\newline(9b1)(9b+1)=(9b)2(1)2(9b-1)(9b+1) = (9b)^2 - (1)^2
  3. Calculate the squares: Calculate the squares of 9b9b and 11.\newline(9b)2=81b2(9b)^2 = 81b^2\newline(1)2=1(1)^2 = 1
  4. Subtract the squares: Subtract the square of 11 from the square of 9b9b.\newline81b2181b^2 - 1
  5. Write the final answer in standard form: Write the final answer in standard form.\newlineThe standard form of a polynomial is written with the highest degree term first, followed by lower degree terms in descending order. Since we only have one term with bb and a constant term, the standard form is:\newline81b2181b^2 - 1

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