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Expand.
Your answer should be a polynomial in standard form.

(9+q)(8-q)=

Expand.\newlineYour answer should be a polynomial in standard form.\newline(9+q)(8q)=(9+q)(8-q)=

Full solution

Q. Expand.\newlineYour answer should be a polynomial in standard form.\newline(9+q)(8q)=(9+q)(8-q)=
  1. Apply distributive property: Apply the distributive property to expand the expression (9+q)(8q)(9+q)(8-q).\newlineDistribute each term in the first parenthesis by each term in the second parenthesis.\newline(9+q)(8q)=9(8)+9(q)+q(8)+q(q)(9+q)(8-q) = 9(8) + 9(-q) + q(8) + q(-q)
  2. Multiply terms: Multiply the terms from the previous step.\newline9(8)=729(8) = 72\newline9(q)=9q9(-q) = -9q\newlineq(8)=8qq(8) = 8q\newlineq(q)=q2q(-q) = -q^2
  3. Combine like terms: Combine like terms from the multiplication results. \newline729q+8qq272 - 9q + 8q - q^2\newlineCombine 9q-9q and 8q8q to get 1q-1q (or simply q-q).\newline72qq272 - q - q^2
  4. Write in standard form: Write the polynomial in standard form, which means ordering the terms from highest degree to lowest degree. q2q+72-q^2 - q + 72

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