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Expand.
Your answer should be a polynomial in standard form.

(9h+3)(-h-1)=

Expand.\newlineYour answer should be a polynomial in standard form.\newline(9h+3)(h1)=(9h+3)(-h-1)=

Full solution

Q. Expand.\newlineYour answer should be a polynomial in standard form.\newline(9h+3)(h1)=(9h+3)(-h-1)=
  1. Apply distributive property: Apply the distributive property to expand the expression (9h+3)(h1)(9h+3)(-h-1).\newlineDistribute each term in the first polynomial (9h+3)(9h+3) with each term in the second polynomial (h1)(-h-1).\newline(9h+3)(h1)=9h(h)+9h(1)+3(h)+3(1)(9h+3)(-h-1) = 9h(-h) + 9h(-1) + 3(-h) + 3(-1)
  2. Multiply the terms: Multiply the terms from the previous step.\newline9h(h)=9h29h(-h) = -9h^2 (Multiplying 9h9h by h-h gives 9h2-9h^2)\newline9h(1)=9h9h(-1) = -9h (Multiplying 9h9h by 1-1 gives 9h-9h)\newline3(h)=3h3(-h) = -3h (Multiplying 33 by h-h gives 9h9h11)\newline9h9h22 (Multiplying 33 by 1-1 gives 9h9h55)
  3. Combine like terms: Combine the like terms from the multiplication results.\newline9h29h3h3-9h^2 - 9h - 3h - 3\newlineCombine 9h-9h and 3h-3h to get 12h-12h.\newline9h212h3-9h^2 - 12h - 3
  4. Write final answer: Write the final answer in standard form, which is the form of a polynomial arranged by descending powers of hh.\newlineThe final answer is 9h212h3-9h^2 - 12h - 3.

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