Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Expand.
Your answer should be a polynomial in standard form.

(5n-5)(2+2n)=

Expand.\newlineYour answer should be a polynomial in standard form.\newline(5n5)(2+2n)=(5n-5)(2+2n)=

Full solution

Q. Expand.\newlineYour answer should be a polynomial in standard form.\newline(5n5)(2+2n)=(5n-5)(2+2n)=
  1. Distribute first term: We distribute the first term of the first binomial, 5n5n, to both terms of the second binomial, 22 and 2n2n. \newline5n×2=10n5n \times 2 = 10n\newline5n×2n=10n25n \times 2n = 10n^2
  2. Distribute second term: Next, we distribute the second term of the first binomial, 5-5, to both terms of the second binomial, 22 and 2n2n.\newline5×2=10-5 \times 2 = -10\newline5×2n=10n-5 \times 2n = -10n
  3. Combine terms: Now, we combine all the terms we have found to get the expanded form. 10n2+10n10n1010n^2 + 10n - 10n - 10
  4. Cancel like terms: We notice that there are like terms that can be combined: 10n10n and 10n-10n cancel each other out.\newline10n2+(10n10n)1010n^2 + (10n - 10n) - 10\newline10n21010n^2 - 10
  5. Final answer: The expression is now fully simplified and in standard form.\newlineThe final answer is 10n21010n^2 - 10.

More problems from Multiply two binomials