Expand. If necessary, combine like terms. (x+3)(x-3)=

Identify values of a and b: Identify the values of a and b. In the expression (x+3)(x-3), a is x and b is 3.Apply difference of squares formula: Apply the difference of squares formula to expand (x+3)(x-3). Using the formula: (a+b)(a-b) = a^2 - b^2 (x+3)(x-3) = x^2 - 3^2Simplify the expression: Simplify the expression x^2 - 3^2. x^2 - 3^2 = x^2 - 9

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Expand. If necessary, combine like terms.

(x+3)(x-3)=

Expand. If necessary, combine like terms. $\newline$ $(x+3)(x-3)=$

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Algebra 1

Multiply two binomials: special cases

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Q. Expand. If necessary, combine like terms.

\newline

(x+3)(x-3)=

Identify values of a and b: Identify the values of a and b. $\newline$ In the expression $(x+3)(x-3)$ , a is $x$ and b is $3$ .
Apply difference of squares formula: Apply the difference of squares formula to expand $(x+3)(x-3)$ . $\newline$ Using the formula: $(a+b)(a-b) = a^2 - b^2$ $\newline$ $(x+3)(x-3) = x^2 - 3^2$
Simplify the expression: Simplify the expression $x^2 - 3^2$ . $\newline$ $x^2 - 3^2 = x^2 - 9$